मराठी

Let F : R → R Be Given by Where [X] Denotes the Greatest Integer Less than Or Equal to X. Then, F(X) is (A) Many-one and onto (B) Many-one and into (C) One-one and into (D) One-one and onto - Mathematics

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प्रश्न

Let

f : R → R be given by

\[f\left( x \right) = \left[ x^2 \right] + \left[ x + 1 \right] - 3\]

where [x] denotes the greatest integer less than or equal to x. Then, f(x) is
 


(d) one-one and onto

पर्याय

  • many-one and onto

  • many-one and into

  • one-one and into

  • one-one and onto

MCQ
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उत्तर

(b) many-one and into

f : R → R 

\[f\left( x \right) = \left[ x^2 \right] + \left[ x + 1 \right] - 3\] 

It is many one function because in this case for two different values of x
we would get the same value of f(x) .

\[For \]
\[x = 1 . 1, 1 . 2 \in R\]
\[f(1 . 1) = \left[ \left( 1 . 1 \right)^2 \right] + \left[ 1 . 1 + 1 \right] - 3\]
\[ = \left[ 1 . 21 \right] + \left[ 2 . 1 \right] - 3\]
\[ = 1 + 2 - 3\]
\[ = 0\]
\[f(1 . 1) = \left[ \left( 1 . 2 \right)^2 \right] + \left[ 1 . 2 + 1 \right] - 3\]
\[ = \left[ 1 . 44 \right] + \left[ 2 . 2 \right] - 3\]
\[ = 1 + 2 - 3\]
\[ = 0\]

It is into function because for the given domain we would only get the integral values of
f(x).
but R is the codomain of the given function.
That means , Codomain\[\neq\]Range Hence, the given function is into function.
Therefore, f(x) is many one and into

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पाठ 2: Functions - Exercise 2.6 [पृष्ठ ७५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 2 Functions
Exercise 2.6 | Q 8 | पृष्ठ ७५

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