मराठी

Let A = R – {2} and B = R – {1}. If f: A → B is a function defined by f(x) = x-1x-2 then show that f is a one-one and an onto function.

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प्रश्न

Let A = R – {2} and B = R – {1}. If f: A `→` B is a function defined by f(x) = `(x - 1)/(x - 2)` then show that f is a one-one and an onto function.

बेरीज
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उत्तर

Let A = R – {2}, B = R – {1}

f: A `→` B s.t. f(x) = `(x - 1)/(x - 2)`

For x1, x2 ∈ A

f(x1) = f(x2)

`\implies (x_1 - 1)/(x_1 - 2) = (x_2 - 1)/(x_2 - 2)` 

`\implies (x_1 - 1)/(x_1 - 2) - 1 = (x_2 - 1)/(x_2 - 2) - 1`

`\implies 1/(x_1 - 2) = 1/(x_2 - 2)`

`\implies` x1 – 2 = x2 – 2

`\implies` x1 = x2

∴ f(x) is one-one function.

Also if f(x) = y, where y ∈ B.

`\implies (x - 1)/(x - 2)` = y 

`\implies` x – 1 = xy – 2y

`\implies` 2y – 1 = xy – x

`\implies` 2y – 1 = x(y – 1)

x = `(2y - 1)/(y - 1) ∈ A`


Clearly every element y ∈ B is associated to x = `(2y - 1)/(y - 1)` of set A.

So Range of f = B `\implies` f is into

Hence f is one-one and onto function.

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