मराठी

If f(x) = [4 – (x – 7)3]1/5 is a real invertible function, then find f–1(x).

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प्रश्न

If f(x) = [4 – (x – 7)3]1/5 is a real invertible function, then find f–1(x).

बेरीज
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उत्तर

Given f(x) = [4 – (x – 7)3]1/5 is a real invertible function.

Let f(x) = y

`\implies` y = [4 – (x – 7)3]1/5

`\implies` y5 = 4 – (x – 7)3

`\implies` (x – 7)3 = 4 – y5

`\implies` x – 7 = [4 – y5]1/3

`\implies` x = 7 + (4 – y5)1/3

`\implies` f1(y) = 7 + (4 – y5)1/3 `          {{:(∵ f(x)  "is invertible"), (∴ f(x) = "y"),(\implies x = f^-1("y")):}`

Hence f1(x) = 7 + (4 – x5)1/3

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