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प्रश्न
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
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उत्तर
On moving down group IV, the higher oxidation state becomes unstable because of the inert pair effect. Pb(IV) is highly unstable and when heated, it reduces to Pb (II).
\[\ce{PbCl_{4(l)} ->[\Delta] PbCl_{2(s)} + Cl_{2(g)}}\]
संबंधित प्रश्न
Explain the difference in properties of diamond and graphite on the basis of their structures.
Elements of group 14 ________.
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Tl2O3
Write suitable chemical equations to show the nature of the following oxide.
B2O3
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
Which of the following is a Lewis acid?
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
The linear shape of CO2 is due to:
(i) sp3 hybridisation of carbon.
(ii) sp hybridisation of carbon.
(iii) pπ – pπ bonding between carbon and oxygen.
(iv) sp2 hybridisation of carbon.
Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Explain the following:
CO2 is a gas whereas SiO2 is a solid.
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Explain the following:
Why does the element silicon, not form a graphite like structure whereas carbon does.
\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.
Which one of the following compounds of Group–14 elements is not known?
