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Question
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
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Solution
On moving down group IV, the higher oxidation state becomes unstable because of the inert pair effect. Pb(IV) is highly unstable and when heated, it reduces to Pb (II).
\[\ce{PbCl_{4(l)} ->[\Delta] PbCl_{2(s)} + Cl_{2(g)}}\]
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