Advertisements
Advertisements
प्रश्न
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.
Advertisements
उत्तर
Carbon, the first member of group 14 possesses a pronounced ability to form stable p-p multiple bonds with itself and with other first row elements such as nitrogen and oxygen. In CO2, both the oxygen atoms are linked with carbon atom by double bonds.
\[\ce{O \overset{σ}{\underset{π}{=}} C \overset{σ}{\underset{π}{=}} O}\]
However, silicon shows its reluctance in forming p-p multiple bonding due to large atomic size. Thus, in Si02, oxygen atoms are linked to silicon atom by single covalent bonds giving three-dimensional network.
\[\begin{array}{cc}
\phantom{.}|\phantom{.........}|\phantom{..}\\
\phantom{.}\ce{O}\phantom{........}\ce{O}\phantom{..}\\
\phantom{.}|\phantom{.........}|\phantom{..}\\
\ce{- O - Si - O - Si - O -}\\
\phantom{.}|\phantom{.........}|\phantom{..}\\\
\phantom{.}\ce{O}\phantom{........}\ce{O}\phantom{..}\\
\phantom{.}|\phantom{.........}|\phantom{..}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
Explain the difference in properties of diamond and graphite on the basis of their structures.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Tl2O3
Write suitable chemical equations to show the nature of the following oxide.
B2O3
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Write suitable chemical equations to show the nature of the following oxide.
CO2
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
Write suitable chemical equations to show the nature of the following oxide.
PbO2
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
The linear shape of CO2 is due to:
(i) sp3 hybridisation of carbon.
(ii) sp hybridisation of carbon.
(iii) pπ – pπ bonding between carbon and oxygen.
(iv) sp2 hybridisation of carbon.
Give reasons for the following:
CCl4 is immiscible in water, whereas SiCl4 is easily hydrolysed.
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Explain the following:
Why does the element silicon, not form a graphite like structure whereas carbon does.
