Advertisements
Advertisements
प्रश्न
Elements of group 14 ________.
पर्याय
exhibit oxidation state of +4 only
exhibit oxidation state of +2 and +4
form M2– and M4+ ions
form M2+ and M4+ ions
Advertisements
उत्तर
Elements of group 14 exhibit oxidation state of +2 and +4.
Explanation:
The elements of group 14 have 4 valence electrons. Therefore, the oxidation state of the group is +4. However, as a result of the inert pair effect, the lower oxidation state becomes more and more stable and the higher oxidation state becomes less stable. Therefore, this group exhibits +4 and +2 oxidation states
| Group 14 element | Oxidation state |
| C | +4 |
| Si | +4 |
| Ge, Sn, Pb | +2, +4 |
संबंधित प्रश्न
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Write suitable chemical equations to show the nature of the following oxide.
Tl2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
B2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
PbO2
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Which of the following is a Lewis acid?
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.
Explain the following:
Carbon shows catenation property but lead does not.
A tetravalent element forms monoxide and dioxide with oxygen. When air is passed over heated element (1273 K), producer gas is obtained. Monoxide of the element is a powerful reducing agent and reduces ferric oxide to iron. Identify the element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer gas and reduction of ferric oxide with the monoxide.
The principal ore of lead is ______.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
