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प्रश्न
Elements of group 14 ________.
विकल्प
exhibit oxidation state of +4 only
exhibit oxidation state of +2 and +4
form M2– and M4+ ions
form M2+ and M4+ ions
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उत्तर
Elements of group 14 exhibit oxidation state of +2 and +4.
Explanation:
The elements of group 14 have 4 valence electrons. Therefore, the oxidation state of the group is +4. However, as a result of the inert pair effect, the lower oxidation state becomes more and more stable and the higher oxidation state becomes less stable. Therefore, this group exhibits +4 and +2 oxidation states
| Group 14 element | Oxidation state |
| C | +4 |
| Si | +4 |
| Ge, Sn, Pb | +2, +4 |
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of C to Pb.
Rationalise the given statement and give a chemical reaction:
Lead (II) chloride reacts with Cl2 to give PbCl4.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
B2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Al2O3
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Explain the following:
Carbon shows catenation property but lead does not.
The principal ore of lead is ______.
Stannous chloride solution when kept in the air turns milky due to the formation of ______.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
