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प्रश्न
Rationalise the given statement and give a chemical reaction:
Lead (II) chloride reacts with Cl2 to give PbCl4.
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उत्तर
Lead belongs to group 14 of the periodic table. The two oxidation states displayed by this group is +2 and +4. On moving down the group, the +2 oxidation state becomes more stable and the +4 oxidation state becomes less stable. This is because of the inert pair effect. Hence, PbCl4 is much less stable than PbCl2. However, the formation of PbCl4 takes place when chlorine gas is bubbled through a saturated solution of PlCl2.
\[\ce{PbCl_{2(s)} + Cl_{2(g)} -> PbCl_{4(l)}}\]
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of B to Tl.
Discuss the pattern of variation in the oxidation states of C to Pb.
Write suitable chemical equations to show the nature of the following oxide.
Tl2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
B2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:
Give reasons for the following:
CCl4 is immiscible in water, whereas SiCl4 is easily hydrolysed.
Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Explain the following:
CO2 is a gas whereas SiO2 is a solid.
Explain the following:
BF3 does not hydrolyse.
Explain the following:
Why does the element silicon, not form a graphite like structure whereas carbon does.
The principal ore of lead is ______.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
