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प्रश्न
Explain the following:
Carbon shows catenation property but lead does not.
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उत्तर
Property of catenation depends upon the strength of element-element bond which, in turn, depends upon the size of the element. Since the atomic size of carbon is much smaller than that of lead, therefore, carbon-carbon bond strength is much higher than that of lead-lead bond. Due to stronger C-C than Pb-Pb bonds, carbon has a much higher tendency for catenation than lead.
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संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of B to Tl.
Discuss the pattern of variation in the oxidation states of C to Pb.
Rationalise the given statement and give a chemical reaction:
Lead (II) chloride reacts with Cl2 to give PbCl4.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Tl2O3
Write suitable chemical equations to show the nature of the following oxide.
B2O3
Write suitable chemical equations to show the nature of the following oxide.
PbO2
Which of the following is a Lewis acid?
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:
The linear shape of CO2 is due to:
(i) sp3 hybridisation of carbon.
(ii) sp hybridisation of carbon.
(iii) pπ – pπ bonding between carbon and oxygen.
(iv) sp2 hybridisation of carbon.
Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Explain the following:
CO2 is a gas whereas SiO2 is a solid.
\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
