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Explain the following: Carbon shows catenation property but lead does not.

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प्रश्न

Explain the following:

Carbon shows catenation property but lead does not.

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उत्तर

Property of catenation depends upon the strength of element-element bond which, in turn, depends upon the size of the element. Since the atomic size of carbon is much smaller than that of lead, therefore, carbon-carbon bond strength is much higher than that of lead-lead bond. Due to stronger C-C than Pb-Pb bonds, carbon has a much higher tendency for catenation than lead.

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३९]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 33.(viii) | पृष्ठ १३९

संबंधित प्रश्न

Discuss the pattern of variation in the oxidation states of C to Pb.


Elements of group 14 ________.


Rationalise the given statement and give a chemical reaction:

Lead is known not to form an iodide, PbI4.


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO


Classify the following oxide as neutral, acidic, basic or amphoteric:

B2O3


Write suitable chemical equations to show the nature of the following oxide.

B2O3


Write suitable chemical equations to show the nature of the following oxide.

Al2O3


Which of the following is a Lewis acid?


The linear shape of CO2 is due to:

(i) sp3 hybridisation of carbon.

(ii) sp hybridisation of carbon.

(iii) pπ – pπ bonding between carbon and oxygen.

(iv) sp2 hybridisation of carbon.


Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.


The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.


Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.


Explain the following:

BF3 does not hydrolyse.


A tetravalent element forms monoxide and dioxide with oxygen. When air is passed over heated element (1273 K), producer gas is obtained. Monoxide of the element is a powerful reducing agent and reduces ferric oxide to iron. Identify the element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer gas and reduction of ferric oxide with the monoxide.


The principal ore of lead is ______. 


Match List I with List II:

List I List II
Coke Carbon atoms are sp3 hybridized.
Diamond Used as a dry lubricant.
Fullerene Used as a reducing agent.
Graphite Cage like molecules

Choose the correct answer from the options given below:


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