Advertisements
Advertisements
प्रश्न
Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Advertisements
उत्तर
Silicon has 3d-orbitals in the valence shell and thus expands its octet giving sp3d2 hybridisation while d-orbitals are not present in the valence shell of carbon. It can undergo ip3-hybridisation only. Thus, carbon is unable to form \[\ce{CF^{2-}6}\] anion.
APPEARS IN
संबंधित प्रश्न
Explain the following reaction.
Silicon is heated with methyl chloride at high temperature in the presence of copper.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Write suitable chemical equations to show the nature of the following oxide.
Tl2O3
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
Rationalise the given statement and give a chemical reaction:
Lead is known not to form an iodide, PbI4.
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
Al2O3
Write suitable chemical equations to show the nature of the following oxide.
B2O3
Write suitable chemical equations to show the nature of the following oxide.
CO2
Write suitable chemical equations to show the nature of the following oxide.
PbO2
The reason for small radius of Ga compared to Al is:
(i) poor screening effect of d and f orbitals.
(ii) increase in nuclear charge.
(iii) presence of higher orbitals.
(iv) higher atomic number.
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.
Explain the following:
Carbon shows catenation property but lead does not.
The principal ore of lead is ______.
Which one of the following compounds of Group–14 elements is not known?
