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Explain the following: Silicon forms SiFX62− ion whereas corresponding fluoro compound of carbon is not known.

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प्रश्न

Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.

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उत्तर

Silicon has 3d-orbitals in the valence shell and thus expands its octet giving sp3d2 hybridisation while d-orbitals are not present in the valence shell of carbon. It can undergo ip3-hybridisation only. Thus, carbon is unable to form \[\ce{CF^{2-}6}\] anion.

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पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३८]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 27.(ii) | पृष्ठ १३८

संबंधित प्रश्‍न

Discuss the pattern of variation in the oxidation states of  B to Tl.


Write suitable chemical equations to show the nature of the following oxide.

Tl2O3


Elements of group 14 ________.


Rationalise the given statement and give a chemical reaction:

Lead (IV) chloride is highly unstable towards heat.


Classify the following oxide as neutral, acidic, basic or amphoteric:

B2O3


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO2


Classify the following oxide as neutral, acidic, basic or amphoteric:

Al2O3


Classify the following oxide as neutral, acidic, basic or amphoteric:

PbO2


Write suitable chemical equations to show the nature of the following oxide.
CO

Which of the following is a Lewis acid?


The reason for small radius of Ga compared to Al is:

(i) poor screening effect of d and f orbitals.

(ii) increase in nuclear charge.

(iii) presence of higher orbitals.

(iv) higher atomic number.


The linear shape of CO2 is due to:

(i) sp3 hybridisation of carbon.

(ii) sp hybridisation of carbon.

(iii) pπ – pπ bonding between carbon and oxygen.

(iv) sp2 hybridisation of carbon.


The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.


Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.


\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.


Which one of the following compounds of Group–14 elements is not known?


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