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प्रश्न
Rationalise the given statement and give a chemical reaction:
Lead is known not to form an iodide, PbI4.
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उत्तर
Lead is known not to form PbI4. Pb (+4) is oxidising in nature and I- is reducing in nature. A combination of Pb(IV) and iodide ion is not stable. Iodide ion is strongly reducing in nature. Pb(IV) oxidises I– to I2 and itself gets reduced to Pb(II).
\[\ce{PbI_4 -> PbI_2 + I_2}\]
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of B to Tl.
Explain the difference in properties of diamond and graphite on the basis of their structures.
Explain the following reaction.
Silicon is heated with methyl chloride at high temperature in the presence of copper.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Elements of group 14 ________.
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
PbO2
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Write suitable chemical equations to show the nature of the following oxide.
CO2
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Explain the following:
Carbon shows catenation property but lead does not.
Explain the following:
BF3 does not hydrolyse.
Explain the following:
Why does the element silicon, not form a graphite like structure whereas carbon does.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
