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प्रश्न
Rationalise the given statement and give a chemical reaction:
Lead is known not to form an iodide, PbI4.
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उत्तर
Lead is known not to form PbI4. Pb (+4) is oxidising in nature and I- is reducing in nature. A combination of Pb(IV) and iodide ion is not stable. Iodide ion is strongly reducing in nature. Pb(IV) oxidises I– to I2 and itself gets reduced to Pb(II).
\[\ce{PbI_4 -> PbI_2 + I_2}\]
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of C to Pb.
Explain the following reaction.
Silicon is heated with methyl chloride at high temperature in the presence of copper.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Elements of group 14 ________.
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
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Classify the following oxide as neutral, acidic, basic or amphoteric:
Tl2O3
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Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Explain the following:
Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.
Explain the following:
Carbon shows catenation property but lead does not.
Explain the following:
Why does the element silicon, not form a graphite like structure whereas carbon does.
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\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.
Which one of the following compounds of Group–14 elements is not known?
