English
Karnataka Board PUCPUC Science Class 11

Rationalise the given statement and give a chemical reaction: Lead is known not to form an iodide, PbI4.

Advertisements
Advertisements

Question

Rationalise the given statement and give a chemical reaction:

Lead is known not to form an iodide, PbI4.

Short/Brief Note
Advertisements

Solution

Lead is known not to form PbI4. Pb (+4) is oxidising in nature and I- is reducing in nature. A combination of Pb(IV) and iodide ion is not stable. Iodide ion is strongly reducing in nature. Pb(IV) oxidises I to I2 and itself gets reduced to Pb(II).

\[\ce{PbI_4 -> PbI_2 + I_2}\]

shaalaa.com
  Is there an error in this question or solution?

RELATED QUESTIONS

Discuss the pattern of variation in the oxidation states of C to Pb.


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO2


Classify the following oxide as neutral, acidic, basic or amphoteric:

Al2O3


Classify the following oxide as neutral, acidic, basic or amphoteric:

PbO2


Write suitable chemical equations to show the nature of the following oxide.
CO

Write suitable chemical equations to show the nature of the following oxide.

Al2O3


Write suitable chemical equations to show the nature of the following oxide.

PbO2


Which of the following is a Lewis acid?


Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:


Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.


Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.


Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.


The principal ore of lead is ______. 


Stannous chloride solution when kept in the air turns milky due to the formation of ______.


\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.


Which one of the following compounds of Group–14 elements is not known?


Match List I with List II:

List I List II
Coke Carbon atoms are sp3 hybridized.
Diamond Used as a dry lubricant.
Fullerene Used as a reducing agent.
Graphite Cage like molecules

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×