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Question
Explain the following:
BF3 does not hydrolyse.
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Solution
Unlike other boron halides, BF3 does not hydrolyse completely. Instead, it hydrolyses incompletely to form boric acid and fluoroboric acid. This is because the HF first formed reacts with H3BO3.
\[\ce{BF3 + 3H2O -> H3BO3 + 3HF] × 4}\]
\[\ce{H3BO3 + 4HF -> H^{+} + [BF4]^{-} + 3H2O] × 3}\]
\[\ce{4BF3 + 3H2O -> H3BO3 + 3[BF4]^{-} + 3H+}\]
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