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प्रश्न
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
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उत्तर
Ionisation enthalpy of carbon (the first element of group 14) is very high (1086 kJ/mol). This is expected owing to its small size. However, on moving down the group to silicon, there is a sharp decrease in the enthalpy (786 kJ). This is because of an appreciable increase in the atomic sizes of elements on moving down the group.
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of B to Tl.
Rationalise the given statement and give a chemical reaction:
Lead (II) chloride reacts with Cl2 to give PbCl4.
Explain the following reaction.
Silicon is heated with methyl chloride at high temperature in the presence of copper.
Write suitable chemical equations to show the nature of the following oxide.
Tl2O3
Rationalise the given statement and give a chemical reaction:
Lead (IV) chloride is highly unstable towards heat.
Rationalise the given statement and give a chemical reaction:
Lead is known not to form an iodide, PbI4.
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO
Classify the following oxide as neutral, acidic, basic or amphoteric:
B2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Al2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
PbO2
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
Which of the following is a Lewis acid?
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:
A tetravalent element forms monoxide and dioxide with oxygen. When air is passed over heated element (1273 K), producer gas is obtained. Monoxide of the element is a powerful reducing agent and reduces ferric oxide to iron. Identify the element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer gas and reduction of ferric oxide with the monoxide.
\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
