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The reason for small radius of Ga compared to Al is: (i) poor screening effect of d and f orbitals. (ii) increase in nuclear charge. (iii) presence of higher orbitals. (iv) higher atomic number.

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प्रश्न

The reason for small radius of Ga compared to Al is:

(i) poor screening effect of d and f orbitals.

(ii) increase in nuclear charge.

(iii) presence of higher orbitals.

(iv) higher atomic number.

टीपा लिहा
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उत्तर

(i) poor screening effect of d and f orbitals.

(ii) increase in nuclear charge.

Explanation:

The additional 10 d-electrons offer poor screening effect for the outer electrons from the increased fluclear charge in Gallium. Hence, atomic radius of Gallium is less than that of aluminium.

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पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 16 | पृष्ठ १३६

संबंधित प्रश्‍न

Discuss the pattern of variation in the oxidation states of  B to Tl.


Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?


Elements of group 14 ________.


Rationalise the given statement and give a chemical reaction:

Lead is known not to form an iodide, PbI4.


Classify the following oxide as neutral, acidic, basic or amphoteric:

B2O3


Classify the following oxide as neutral, acidic, basic or amphoteric:

Tl2O3


Write suitable chemical equations to show the nature of the following oxide.
CO

Write suitable chemical equations to show the nature of the following oxide.

B2O3


Write suitable chemical equations to show the nature of the following oxide.

CO2


Which of the following is a Lewis acid?


Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:


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(i) sp3 hybridisation of carbon.

(ii) sp hybridisation of carbon.

(iii) pπ – pπ bonding between carbon and oxygen.

(iv) sp2 hybridisation of carbon.


Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.


Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.


Explain the following:

BF3 does not hydrolyse.


The principal ore of lead is ______. 


Stannous chloride solution when kept in the air turns milky due to the formation of ______.


\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.


Match List I with List II:

List I List II
Coke Carbon atoms are sp3 hybridized.
Diamond Used as a dry lubricant.
Fullerene Used as a reducing agent.
Graphite Cage like molecules

Choose the correct answer from the options given below:


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