Advertisements
Advertisements
प्रश्न
The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.
Advertisements
उत्तर
In group 13 and 14, as we move down the group, the tendency of s-electrons of the valence shell to participate in bond formation decreases. This is due to ineffective shielding of s-electrons of the valence shell by the intervening d- and f-electrons. This is called inert pair effect.
Due to this, s-electrons of the valence shell of group 13 and 14 are unable to participate in bonding. Hence, +1 and +2 oxidation states, in group 13 and 14 respectively, become -more stable with increasing atomic number.
APPEARS IN
संबंधित प्रश्न
Discuss the pattern of variation in the oxidation states of C to Pb.
Explain the difference in properties of diamond and graphite on the basis of their structures.
Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?
Elements of group 14 ________.
Classify the following oxide as neutral, acidic, basic or amphoteric:
B2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
SiO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
CO2
Classify the following oxide as neutral, acidic, basic or amphoteric:
Al2O3
Classify the following oxide as neutral, acidic, basic or amphoteric:
PbO2
Write suitable chemical equations to show the nature of the following oxide.
SiO2
Write suitable chemical equations to show the nature of the following oxide.
Al2O3
Write suitable chemical equations to show the nature of the following oxide.
PbO2
Which of the following is a Lewis acid?
The linear shape of CO2 is due to:
(i) sp3 hybridisation of carbon.
(ii) sp hybridisation of carbon.
(iii) pπ – pπ bonding between carbon and oxygen.
(iv) sp2 hybridisation of carbon.
Give reasons for the following:
CCl4 is immiscible in water, whereas SiCl4 is easily hydrolysed.
Carbon and silicon both belong to the group 14, but inspite of the stoichiometric similarity, the dioxides, (i.e., carbon dioxide and silicon dioxide), differ in their structures. Comment.
Explain the following:
BF3 does not hydrolyse.
Which one of the following compounds of Group–14 elements is not known?
Match List I with List II:
| List I | List II |
| Coke | Carbon atoms are sp3 hybridized. |
| Diamond | Used as a dry lubricant. |
| Fullerene | Used as a reducing agent. |
| Graphite | Cage like molecules |
Choose the correct answer from the options given below:
