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The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain. - Chemistry

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प्रश्न

The +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number. Explain.

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उत्तर

In group 13 and 14, as we move down the group, the tendency of s-electrons of the valence shell to participate in bond formation decreases. This is due to ineffective shielding of s-electrons of the valence shell by the intervening d- and f-electrons. This is called inert pair effect.

Due to this, s-electrons of the valence shell of group 13 and 14 are unable to participate in bonding. Hence, +1 and +2 oxidation states, in group 13 and 14 respectively, become -more stable with increasing atomic number.

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पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३८]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 28 | पृष्ठ १३८

संबंधित प्रश्‍न

Rationalise the given statement and give a chemical reaction:

Lead (II) chloride reacts with Cl2 to give PbCl4.


Explain why is there a phenomenal decrease in ionisation enthalpy from carbon to silicon?


Elements of group 14 ________.


Rationalise the given statement and give a chemical reaction:

Lead is known not to form an iodide, PbI4.


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO


Classify the following oxide as neutral, acidic, basic or amphoteric:

B2O3


Classify the following oxide as neutral, acidic, basic or amphoteric:

CO2


Write suitable chemical equations to show the nature of the following oxide.
CO

Write suitable chemical equations to show the nature of the following oxide.

SiO2


Write suitable chemical equations to show the nature of the following oxide.

PbO2


Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order:


The linear shape of CO2 is due to:

(i) sp3 hybridisation of carbon.

(ii) sp hybridisation of carbon.

(iii) pπ – pπ bonding between carbon and oxygen.

(iv) sp2 hybridisation of carbon.


Give reasons for the following:

CCl4 is immiscible in water, whereas SiCl4 is easily hydrolysed.


Explain the following:

CO2 is a gas whereas SiO2 is a solid.


Explain the following:

Silicon forms \[\ce{SiF^{2-}6}\] ion whereas corresponding fluoro compound of carbon is not known.


Stannous chloride solution when kept in the air turns milky due to the formation of ______.


\[\ce{SiCl4 ->[H2O] (A) ->[\Delta] (B) ->[Na2CO3][heat] (C)}\]. The Compound C is ______.


Which one of the following compounds of Group–14 elements is not known?


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