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प्रश्न
How many geometrical isomers are possible in the following coordination entity?
[Cr(C2O4)3]3−
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उत्तर
It is a complex [Cr(C2O4)3]3− of the type [M(AA)3]± and is unable to show geometrical isomerism. Hence, no geometric isomer is possible as it is a bidentate ligand.

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संबंधित प्रश्न
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K[Cr(H2O)2(C2O4)2]
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[Co(en)3]Cl3
Indicate the type of isomerism exhibited by the following complex and draw the structure for the isomer:
[Pt(NH3)(H2O)Cl2]
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Indicate the types of isomerism exhibited by the following complex and draw the structure for these isomer: \[\ce{[Pt(NH3)(H2O)Cl2]}\]
Indicate the types of isomerism exhibited by the following complexes and draw the structure for these isomer:
\[\ce{[Pt(NH3)(H2O)Cl2]}\]
Indicate the type of isomerism exhibited by the following complex and draw the structure for the isomer:
\[\ce{[Pt(NH3 )(H2O)Cl2]}\]
