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Question
How many geometrical isomers are possible in the following coordination entity?
[Cr(C2O4)3]3−
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Solution
It is a complex [Cr(C2O4)3]3− of the type [M(AA)3]± and is unable to show geometrical isomerism. Hence, no geometric isomer is possible as it is a bidentate ligand.
RELATED QUESTIONS
Explain cationic complexes and anionic complexes of co-ordination compounds.
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