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प्रश्न
The figure represents graphically the velocity of a car moving along a straight road over a period of 100 hours.
Calculate the distance travelled in the last 40 h.
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उत्तर
Distance travelled in last 40 hour would be equal to area under graph during that time = 50 x (100 - 60) + `1/2`x(100 - 60) x(100 - 50).
S = 2000 + 1000 = 3000 km.
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संबंधित प्रश्न
What is the difference between distance travelled by a body and its displacement ? Explain with the
help of a diagram.
Differentiate between distance and displacement.
Figure (a) shows the velocity-time graph for the motion of a body. Use it to find the displacement of the body at t = 1 s, 2 s, 3 s and 4 s, then draw on Figure (b), the displacement-time graph for it.
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| (a) | (b) |
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
State how is the distance travelled in any part determined from this graph .
A car starting from rest accelerates uniformly to acquire a speed 20 km h-1 in 30 min. The distance travelled by a car in this time interval will be _____________
A body starts from rest with uniform acceleration 2 m s-2. Find the distance covered by the body in 2 s.
Give an example of a body which covers a certain distance, but its displacement is zero.
Ashok starts from his house and travels 3 km to reach his school. On finding the school gates closed, he returns to his house. What is?
The distance traveled by Ashok.
The displacement is zero when the initial and final positions are ______.
Give one example where the displacement is zero but the distance travelled is not zero.
