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प्रश्न
Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?
(i) \[\ce{[MnCl6]^{3-}}\]
(ii) \[\ce{[FeF6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
(iv) \[\ce{[Ni(NH3)6]^{2+}}\]
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उत्तर
(i) \[\ce{[MnCl6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
Explanation:
\[\ce{[MnCl6]^{3-} : MN^{3+} (3d^4)}\]
| `↑` | `↑` | `↑` | `↑` |
\[\ce{[CoF6]^{3-} : Co^{3+} (3d^6)}\]
| `↑↓` | `↑` | `↑` | `↑` | `↑` |
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संबंधित प्रश्न
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| Column I (Complex ion) | Column II (Hybridisation, number of unpaired electrons) |
| A. \[\ce{[Cr(H2O)6]^{3+}}\] | 1. dsp2, 1 |
| B. \[\ce{[Co(CN)4]^{2-}}\] | 2. sp3d2, 5 |
| C. \[\ce{[Ni(NH3)6]^{2+}}\] | 3. d2sp3, 3 |
| D. \[\ce{[MnF6]^{4-}}\] | 4. sp3, 4 |
| 5. sp3d2, 2 |
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Choose the correct answer from the options given below:
