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Atomic number of Mn,Fe,Co and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons? (i) [MnClX6]X3− (ii)

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प्रश्न

Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?

(i) \[\ce{[MnCl6]^{3-}}\]

(ii) \[\ce{[FeF6]^{3-}}\]

(iii) \[\ce{[CoF6]^{3-}}\]

(iv) \[\ce{[Ni(NH3)6]^{2+}}\]

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उत्तर

(i) \[\ce{[MnCl6]^{3-}}\]

(iii) \[\ce{[CoF6]^{3-}}\]

Explanation:

\[\ce{[MnCl6]^{3-} : MN^{3+} (3d^4)}\]

`↑` `↑` `↑` `↑`  

\[\ce{[CoF6]^{3-} : Co^{3+} (3d^6)}\]

`↑↓` `↑` `↑` `↑` `↑`
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अध्याय 9: Coordination Compounds - Exercises [पृष्ठ १२२]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 9 Coordination Compounds
Exercises | Q II. 16. | पृष्ठ १२२

संबंधित प्रश्न

On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.


How does the magnitude of Δo decide the actual configuration of d orbitals in a coordination entity?


 Write the electronic configuration of Fe(III) on the basis of crystal field theory when it forms an octahedral complex in the presence of (i) strong field, and (ii) weak field ligand. (Atomic no.of Fe=26) 


The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.


Atomic number of \[\ce{Mn}\], \[\ce{Fe}\] and \[\ce{Co}\] are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

(i) \[\ce{[Co(NH3)6]^{3+}}\]

(ii) \[\ce{[Mn(CN)6]^{3-}}\] 

(iii) \[\ce{[Fe(CN)6]^{4-}}\]

(iv) \[\ce{[Fe(CN)6]^{3-}}\]


Why are low spin tetrahedral complexes not formed?


Arrange following complex ions in increasing order of crystal field splitting energy (∆O):

\[\ce{[Cr(Cl)6]^{3-}, [Cr(CN)6]^{3-}, [Cr(NH3)6]^{3+}}\].


Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

\[\ce{[CoF6]^{3-}, [Co(H2O)6]^{2+}, [Co(Cn)6]^{3-}}\]


The CFSE for octahedral [CoCl6]−4 is 18,000 cm−1. What will be the CFSE for tetrahedral [CoCl3]−2?


[Ni(H2O)6]2+ (aq) is green in colour whereas [Ni(H2O)4 (en)]2+ (aq)is blue in colour, give reason in support of your answer.


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1 

Draw the crystal field splitting diagram for the above complex.


Considering crystal field theory, strong-field ligands such as CN–:


Crystal field stabilising energy for high spind4 octahedral complex is:-


Using crystal field theory, write the electronic configuration of d5 ion, if Δ0 > P.


What is crystal field splitting energy?


Read the passage carefully and answer the questions that follow.

Crystal field splitting by various ligands

Metal complexes show different colours due to d-d transitions. The complex absorbs light of specific wavelength to promote the electron from t2g to eg level. The colour of the complex is due to the transmitted light, which is complementary of the colour absorbed.

The wave number of light absorbed by different complexes of Cr ion are given below:

Complex Wavenumber of light absorbed (cm-1) Energy of light absorbed (kJ/mol)
[CrA6]3- 13,640 163
[CrB6]3+ 17,830 213
[CrC6]3+ 21,680 259
[CrD6]3- 26,280 314

Answer the following questions:

(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?

OR

Which of the two, “A” or “D” will be a weak field ligand? Why?

(b) Which of the complexes will be violet in colour? [CrA6]3- or [CrB6]3+ and why?
(Given: If 560 - 570 nm of light is absorbed, the colour of the complex observed is violet.)

(c) If the ligands attached to Cr3+ ion in the complexes given in the table above are water, cyanide ion, chloride ion, and ammonia (not in this order).

Identify the ligand, write the formula and IUPAC name of the following:

  1. [CrA6]3-
  2. [CrC6]3+

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