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Question
Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?
(i) \[\ce{[MnCl6]^{3-}}\]
(ii) \[\ce{[FeF6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
(iv) \[\ce{[Ni(NH3)6]^{2+}}\]
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Solution
(i) \[\ce{[MnCl6]^{3-}}\]
(iii) \[\ce{[CoF6]^{3-}}\]
Explanation:
\[\ce{[MnCl6]^{3-} : MN^{3+} (3d^4)}\]
| `↑` | `↑` | `↑` | `↑` |
\[\ce{[CoF6]^{3-} : Co^{3+} (3d^6)}\]
| `↑↓` | `↑` | `↑` | `↑` | `↑` |
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