English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Why are low spin tetrahedral complexes not formed?

Advertisements
Advertisements

Question

Why are low spin tetrahedral complexes not formed?

Very Short Answer
Advertisements

Solution

For tetrahedral complexes, the crystal field splitting energy is too low. It is lower than the pairing energy, so the pairing of electrons is not favoured, and therefore the complexes cannot form low-spin complexes.

shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Coordination Compounds - Exercises [Page 124]

APPEARS IN

NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 9 Coordination Compounds
Exercises | Q III. 29. | Page 124

RELATED QUESTIONS

On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.


The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.


How are the following conversions carried out?

Benzoic acid into metanitrobenzoic acid.


State the superiority of crystal field theory over valence bond theory.


Why are low spin tetrahedral complexes rarely observed?


 Write the electronic configuration of Fe(III) on the basis of crystal field theory when it forms an octahedral complex in the presence of (i) strong field, and (ii) weak field ligand. (Atomic no.of Fe=26) 


Atomic number of \[\ce{Mn}\], \[\ce{Fe}\] and \[\ce{Co}\] are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

(i) \[\ce{[Co(NH3)6]^{3+}}\]

(ii) \[\ce{[Mn(CN)6]^{3-}}\] 

(iii) \[\ce{[Fe(CN)6]^{4-}}\]

(iv) \[\ce{[Fe(CN)6]^{3-}}\]


Give the electronic configuration of the following complexes on the basis of Crystal Field Splitting theory.

\[\ce{[CoF6]^{3-}, [Fe(CN)6]^{4-} and [Cu(NH3)6]^{2+}}\].


Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

The CFSE for octahedral [CoCl6]−4 is 18,000 cm−1. What will be the CFSE for tetrahedral [CoCl3]−2?


The correct order of increasing crystal field strength in following series:


Crystal field stabilising energy for high spind4 octahedral complex is:-


The CFSE of [CoCl6]3– is 18000 cm–1 the CFSE for [CoCl4] will be ______.


On the basis of Crystal Field theory, write the electronic configuration for the d5 ion with a strong field ligand for which Δ0 > P.


Read the passage carefully and answer the questions that follow.

Crystal field splitting by various ligands

Metal complexes show different colours due to d-d transitions. The complex absorbs light of specific wavelength to promote the electron from t2g to eg level. The colour of the complex is due to the transmitted light, which is complementary of the colour absorbed.

The wave number of light absorbed by different complexes of Cr ion are given below:

Complex Wavenumber of light absorbed (cm-1) Energy of light absorbed (kJ/mol)
[CrA6]3- 13,640 163
[CrB6]3+ 17,830 213
[CrC6]3+ 21,680 259
[CrD6]3- 26,280 314

Answer the following questions:

(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?

OR

Which of the two, “A” or “D” will be a weak field ligand? Why?

(b) Which of the complexes will be violet in colour? [CrA6]3- or [CrB6]3+ and why?
(Given: If 560 - 570 nm of light is absorbed, the colour of the complex observed is violet.)

(c) If the ligands attached to Cr3+ ion in the complexes given in the table above are water, cyanide ion, chloride ion, and ammonia (not in this order).

Identify the ligand, write the formula and IUPAC name of the following:

  1. [CrA6]3-
  2. [CrC6]3+

The value of the spin only magnetic moment for one of the following configurations is 2.84 BM. The correct one is:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×