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Questions
Using crystal field theory, write the electronic configuration of d5 ion, if Δ0 > P.
Write the electronic configuration of d5 ion when Δ0 > P.
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Solution
When the crystal field splitting energy (Δ0) is greater than the pairing energy (P), electrons prefer to pair up in the lower‑energy t2g orbitals rather than occupy the higher‑energy eg orbitals. This situation corresponds to a strong field ligand and results in a low‑spin complex.
Therefore, for a d5 ion in an octahedral field, the electronic configuration becomes `t_(2g)^5` `e_g^0`, meaning that no electron enters the eg orbitals.
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