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An aqueous pink solution of cobalt (II) chloride changes to deep blue on addition of excess of HCl. This is because: (i) [Co(HX2O)X6]X2+ is transformed into [CoClX6]4− (ii) [Co(HX

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प्रश्न

An aqueous pink solution of cobalt (II) chloride changes to deep blue on addition of excess of HCl. This is because:

(i) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl6]}^{4-}\]

(ii) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl4]}^{2-}\]

(iii) tetrahedral complexes have smaller crystal field splitting than octahedral complexes.

(iv) tetrahedral complexes have larger crystal field splitting than octahedral complex.

टीपा लिहा
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उत्तर

(ii) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl4]}^{2-}\]

(iii) tetrahedral complexes have smaller crystal field splitting than octahedral complexes.

Explanation:

Aqueous pink solution of cobalt (II) chloride is due to electronic transition of electron from t2g to eg energy level of \[\ce{[Co(H2O)6]^{2+}}\] complex. When excess of HCl is added to this solution

(i) \[\ce{[Co(H2O)6]^{2+}}\] is transformed into \[\ce{[CoCl4]^{2-}}\].

(ii) Tetrahedral complexes have smaller crystal field splitting than octahedral complexes because Δr = `4/9` Δ0 

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पाठ 9: Coordination Compounds - Exercises [पृष्ठ १२३]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 9 Coordination Compounds
Exercises | Q II. 18. | पृष्ठ १२३

संबंधित प्रश्‍न

On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.


On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.


Draw the structures of the following :
(1) XeF6
(2) IF7


The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.


Atomic number of \[\ce{Mn, Fe, Co}\] and Ni are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?

(i) \[\ce{[MnCl6]^{3-}}\]

(ii) \[\ce{[FeF6]^{3-}}\]

(iii) \[\ce{[CoF6]^{3-}}\]

(iv) \[\ce{[Ni(NH3)6]^{2+}}\]


Why are low spin tetrahedral complexes not formed?


\[\ce{CuSO4 . 5H2O}\] is blue in colour while \[\ce{CuSO4}\] is colourless. Why?


Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

\[\ce{[FeF6]^{3-}, [Fe(H2O)6]^{2+}, [Fe(CN)6]^{4-}}\]


Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg1 

Draw the crystal field splitting diagram for the above complex.


Considering crystal field theory, strong-field ligands such as CN–:


For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements:

  1. Both the complexes can be high spin.
  2. Ni(II) complex can very rarely below spin.
  3. With strong field Ligands, Mn(II) complexes can be low spin.
  4. Aqueous solution of Mn (II) ions is yellow in colour.

The correct statements are:


Consider that d6 metal ion (M2+) forms a complex with aqua ligands and the spin only magnetic moment of the complex is 4.90 BM. The geometry and the crystal field stabilization energy of the complex are ______.


On the basis of Crystal Field theory, write the electronic configuration for the d5 ion with a strong field ligand for which Δ0 > P.


On the basis of crystal field theory, write the electronic configuration for the d5 ion with a weak ligand for which Δ0 < P.


On the basis of crystal field theory, write the electronic configuration for d4 with a strong field ligand for which Δ0 > P.


Read the passage carefully and answer the questions that follow.

Crystal field splitting by various ligands

Metal complexes show different colours due to d-d transitions. The complex absorbs light of specific wavelength to promote the electron from t2g to eg level. The colour of the complex is due to the transmitted light, which is complementary of the colour absorbed.

The wave number of light absorbed by different complexes of Cr ion are given below:

Complex Wavenumber of light absorbed (cm-1) Energy of light absorbed (kJ/mol)
[CrA6]3- 13,640 163
[CrB6]3+ 17,830 213
[CrC6]3+ 21,680 259
[CrD6]3- 26,280 314

Answer the following questions:

(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?

OR

Which of the two, “A” or “D” will be a weak field ligand? Why?

(b) Which of the complexes will be violet in colour? [CrA6]3- or [CrB6]3+ and why?
(Given: If 560 - 570 nm of light is absorbed, the colour of the complex observed is violet.)

(c) If the ligands attached to Cr3+ ion in the complexes given in the table above are water, cyanide ion, chloride ion, and ammonia (not in this order).

Identify the ligand, write the formula and IUPAC name of the following:

  1. [CrA6]3-
  2. [CrC6]3+

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