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प्रश्न
On the basis of crystal field theory, write the electronic configuration for d4 with a strong field ligand for which Δ0 > P.
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उत्तर
If Δ0 > P, the electronic configuration of the d4 ion will be \[\ce{t^4_{2g}e^0_{g}}\] as it is associated with a strong field and low-spin situation.
संबंधित प्रश्न
How does the magnitude of Δo decide the actual configuration of d orbitals in a coordination entity?
Why are low spin tetrahedral complexes rarely observed?
The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, \[\ce{[Co(NH3)6]^{3+}}\], \[\ce{[Co(CN)6]^{3-}}\], \[\ce{[Co(H2O)6]^{3+}}\]
The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.
Why are low spin tetrahedral complexes not formed?
Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?
The correct order of increasing crystal field strength in following series:
What is the difference between a weak field ligand and a strong field ligand?
For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements:
- Both the complexes can be high spin.
- Ni(II) complex can very rarely below spin.
- With strong field Ligands, Mn(II) complexes can be low spin.
- Aqueous solution of Mn (II) ions is yellow in colour.
The correct statements are:
Consider that d6 metal ion (M2+) forms a complex with aqua ligands and the spin only magnetic moment of the complex is 4.90 BM. The geometry and the crystal field stabilization energy of the complex are ______.
