मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

The CFSE for octahedral [CoClX6]X4− is 18,000 cm–1. The CFSE for tetrahedral [CoClX4]X2− will be ______.

Advertisements
Advertisements

प्रश्न

The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.

पर्याय

  • 18,000 cm–1

  • 16,000 cm–1

  • 8,000 cm–1

  • 20,000 cm–1

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be 8,000 cm–1.

Explanation:

CFSE for octahedral and tetrahedral complex is related as 

`Δ^t = 4/9 Δ_o`

Where `Δ_o` = CFSE for octahedral complex

`Δ_o` = CFSE for tetrahedral complex

`Δ_o` = 18000 cm–1

`Δ_t = 4/9 xx 18000` = 8000 cm–1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 9: Coordination Compounds - Exercises [पृष्ठ १२१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 9 Coordination Compounds
Exercises | Q I. 8. | पृष्ठ १२१

संबंधित प्रश्‍न

On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.


Draw figure to show the splitting of d orbitals in an octahedral crystal field.


Draw the structures of the following :
(1) XeF6
(2) IF7


The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, \[\ce{[Co(NH3)6]^{3+}}\], \[\ce{[Co(CN)6]^{3-}}\], \[\ce{[Co(H2O)6]^{3+}}\]


Atomic number of \[\ce{Mn}\], \[\ce{Fe}\] and \[\ce{Co}\] are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

(i) \[\ce{[Co(NH3)6]^{3+}}\]

(ii) \[\ce{[Mn(CN)6]^{3-}}\] 

(iii) \[\ce{[Fe(CN)6]^{4-}}\]

(iv) \[\ce{[Fe(CN)6]^{3-}}\]


On the basis of crystal field theory explain why Co(III) forms paramagnetic octahedral complex with weak field ligands whereas it forms diamagnetic octahedral complex with strong field ligands.


Why are low spin tetrahedral complexes not formed?


Give the electronic configuration of the following complexes on the basis of Crystal Field Splitting theory.

\[\ce{[CoF6]^{3-}, [Fe(CN)6]^{4-} and [Cu(NH3)6]^{2+}}\].


Arrange following complex ions in increasing order of crystal field splitting energy (∆O):

\[\ce{[Cr(Cl)6]^{3-}, [Cr(CN)6]^{3-}, [Cr(NH3)6]^{3+}}\].


\[\ce{CuSO4 . 5H2O}\] is blue in colour while \[\ce{CuSO4}\] is colourless. Why?


Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg

Draw the crystal field splitting diagram for the above complex.


Considering crystal field theory, strong-field ligands such as CN:


Crystal field stabilising energy for high spind4 octahedral complex is:-


What is the difference between a weak field ligand and a strong field ligand?


For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements:

  1. Both the complexes can be high spin.
  2. Ni(II) complex can very rarely below spin.
  3. With strong field Ligands, Mn(II) complexes can be low spin.
  4. Aqueous solution of Mn (II) ions is yellow in colour.

The correct statements are:


The complex that has highest crystal field splitting energy (Δ) is ______.


Read the passage carefully and answer the questions that follow.

Crystal field splitting by various ligands

Metal complexes show different colours due to d-d transitions. The complex absorbs light of specific wavelength to promote the electron from t2g to eg level. The colour of the complex is due to the transmitted light, which is complementary of the colour absorbed.

The wave number of light absorbed by different complexes of Cr ion are given below:

Complex Wavenumber of light absorbed (cm-1) Energy of light absorbed (kJ/mol)
[CrA6]3- 13,640 163
[CrB6]3+ 17,830 213
[CrC6]3+ 21,680 259
[CrD6]3- 26,280 314

Answer the following questions:

(a) Out of ligands "A", "B", "C" and "D", which ligand causes maximum crystal field splitting? Why?

OR

Which of the two, “A” or “D” will be a weak field ligand? Why?

(b) Which of the complexes will be violet in colour? [CrA6]3- or [CrB6]3+ and why?
(Given: If 560 - 570 nm of light is absorbed, the colour of the complex observed is violet.)

(c) If the ligands attached to Cr3+ ion in the complexes given in the table above are water, cyanide ion, chloride ion, and ammonia (not in this order).

Identify the ligand, write the formula and IUPAC name of the following:

  1. [CrA6]3-
  2. [CrC6]3+

On the basis of Crystal Field Theory, write the electronic configuration of d4 ion if Δ0 > P.


The correct order of the wavelength of light absorbed by the following complexes is:

  1. [Co(NH3)6]3+
  2. [Co(CN)6]3−
  3. [Cu(H2O)4]2+
  4. [Ti(H2O)6]3+

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×