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How does the magnitude of Δ0 decide the actual configuration of d orbitals in a coordination entity? - Chemistry

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प्रश्न

How does the magnitude of Δ0 decide the actual configuration of d orbitals in a coordination entity?

लघु उत्तर
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उत्तर

  1. If Δ0 < P, the fourth electron enters one of the eg orbitals giving the configuration \[\ce{t^3_{2g}e^1_g}\]. Ligands for which Δ0 < P are known as weak field ligands and form high spin complexes.
  2. If Δ0 > P, it becomes more energetically favourable for the fourth electron to occupy a t2g orbital with configuration \[\ce{t^4_{2g}e^0_g}\]. Ligands which produce this effect are known as strong field ligands and form low spin complexes.
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पाठ 5: Coordinate Compounds - Exercises [पृष्ठ १३९]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 5 Coordinate Compounds
Exercises | Q 5.18 (ii) | पृष्ठ १३९
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
पाठ 9 Coordination Compounds
'NCERT TEXT-BOOK' Exercises | Q 9.18 (ii) | पृष्ठ ५५९

संबंधित प्रश्‍न

On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.


On the basis of crystal field theory, write the electronic configuration for d4 ion if ∆0 < P.


The hexaquo manganese (II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.


State the superiority of crystal field theory over valence bond theory.


Draw the structures of the following :
(1) XeF6
(2) IF7


The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, \[\ce{[Co(NH3)6]^{3+}}\], \[\ce{[Co(CN)6]^{3-}}\], \[\ce{[Co(H2O)6]^{3+}}\]


The CFSE for octahedral \[\ce{[CoCl6]^{4-}}\] is 18,000 cm–1. The CFSE for tetrahedral \[\ce{[CoCl4]^{2-}}\] will be ______.


Arrange following complex ions in increasing order of crystal field splitting energy (∆O):

\[\ce{[Cr(Cl)6]^{3-}, [Cr(CN)6]^{3-}, [Cr(NH3)6]^{3+}}\].


\[\ce{CuSO4 . 5H2O}\] is blue in colour while \[\ce{CuSO4}\] is colourless. Why?


Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code:

Column I (Complex ion) Column II (Hybridisation, number of unpaired electrons)
A. \[\ce{[Cr(H2O)6]^{3+}}\] 1. dsp2, 1
B. \[\ce{[Co(CN)4]^{2-}}\] 2. sp3d2, 5
C. \[\ce{[Ni(NH3)6]^{2+}}\] 3. d2sp3, 3
D. \[\ce{[MnF6]^{4-}}\] 4. sp3, 4
  5. sp3d2, 2

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

\[\ce{[FeF6]^{3-}, [Fe(H2O)6]^{2+}, [Fe(CN)6]^{4-}}\]


In a coordination entity, the electronic configuration of the central metal ion is t2g3 eg

Draw the crystal field splitting diagram for the above complex.


Considering crystal field theory, strong-field ligands such as CN:


The CFSE of [CoCl6]3– is 18000 cm–1 the CFSE for [CoCl4] will be ______.


For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements:

  1. Both the complexes can be high spin.
  2. Ni(II) complex can very rarely below spin.
  3. With strong field Ligands, Mn(II) complexes can be low spin.
  4. Aqueous solution of Mn (II) ions is yellow in colour.

The correct statements are:


On the basis of crystal field theory, write the electronic configuration for d4 with a strong field ligand for which Δ0 > P.


On the basis of Crystal Field Theory, write the electronic configuration of d4 ion if Δ0 > P.


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