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B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई chapter 19 - Trigonometry [Latest edition]

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B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई chapter 19 - Trigonometry - Shaalaa.com
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Solutions for Chapter 19: Trigonometry

Below listed, you can find solutions for Chapter 19 of CISCE B Nirmala Shastry for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई.


EXERCISE 19AEXERCISE 19BEXERCISE 19CMULTIPLE CHOICE QUESTIONS.MISCELLANEOUS EXERCISE
EXERCISE 19A [Page 231]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई 19 Trigonometry EXERCISE 19A [Page 231]

I. 1.Page 231

Find sin θ, cos θ and tan (90° - θ).

I. 2.Page 231

Find sin(90° - θ), cos θ and tan θ.

I. 3.Page 231

If sin θ = `5/13` and AC = 52 cm, find AB, BC and tan θ.

I. 4.Page 231

If cos θ = 0.96 and AB = 24 cm, find BC, AC and cot θ.

I. 5.Page 231

Find cos α and sin β.

I. 6.Page 231

Find sin θ + cos θ, and sec α + tan α in the following figure.

I. 7. (i)Page 231

Find sec x + tan x

I. 7. (ii)Page 231

cosy − sin y

I. 8.Page 231

Find tan θ + cot α, sin θ, cos α.

II. 1.Page 231

If cos θ = `11/61`, find tan θ.

II. 2.Page 231

If sin θ = `5/13`, find sec θ + tan θ.

II. 3.Page 231

If sin θ = 0.6, find sec θ + tan θ.

II. 4.Page 231

If cos θ = 0.28, find cosec θ - cot θ.

II. 5.Page 231

If 12 sin θ = 35 cos θ, find `(sin θ − cos θ)/(sin θ + cos θ)`

II. 6.Page 231

12 cos θ - 16 sin θ = 0, find 2 sin θ + cos θ.

II. 7.Page 231

If tan θ = `p/q,` show that `(p sin θ – q cos θ)/(p sin θ + q cos θ) = (p^2 − q^2)/(p^2 + q^2)`

II. 8. (i)Page 231

If sin A = `3/5 and cos B = 12/13`, evaluate:

sec2A

II. 8. (ii)Page 231

If sin A = `3/5 and cos B = 12/13`, evaluate:

tan A + tan B

II. 9.Page 231

If 5 tan θ = 4, find the value of `(5 sin θ − 3 cos θ)/(5 sin θ + 2 cos θ)`

EXERCISE 19B [Page 233]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई 19 Trigonometry EXERCISE 19B [Page 233]

I. 1.Page 233

Find the angle θ in the following, if 0° < θ < 90°.

sin θ = cos 75°

I. 2.Page 233

Find the angle θ in the following, if 0° < θ < 90°.

cos θ = sin 48°

I. 3.Page 233

Find the angle θ in the following, if 0° < θ < 90°.

cos θ = sin θ

I. 4.Page 233

Find the angle θ in the following, if 0° < θ < 90°.

cos 2θ = sin θ

I. 5Page 233

Find the angle θ in the following, if 0° < θ < 90°.

tan `θ/2 = cot 2θ`

I. 6Page 233

Find the angle θ in the following, if 0° < θ < 90°.

sin (2θ − 10°) = cos (θ + 40°)

II. 1.Page 233

Evaluate without using a trigonometric table:

`(3 sin 23°)/(cos 67°) − (tan 64°)/(cot 26°)`

II. 2.Page 233

Evaluate without using a trigonometric table:

`(Cos⁡70°)/(sin⁡20°)` + cos 36° cosec 54°

II. 3.Page 233

Evaluate without using a trigonometric table:

`(cot 38°)/(tan 52°) + (sec 25°)/("cosec" 65°) − (3 tan 35°)/(cot 55°)`

II. 4.Page 233

Evaluate without using a trigonometric table:

`sin 48°  sec 42° + (sec 50°)/ ("cosec"  40°)`

II. 5.Page 233

Evaluate without using a trigonometric table:

Cos 20° cosec 70° + `(tan⁡34°)/(cot⁡56°)`

II. 6.Page 233

Evaluate without using a trigonometric table:

`(3 sin 32°)/(cos 58°) + (4 tan 46°)/(cot 44°) − (5 sec 62°)/("cosec" 28°)`

II. 7.Page 233

Evaluate without using a trigonometric table:

`(2 tan 36°)/(cot 54°) + (3 cot 38°)/(tan 52°) − (2 sec 41°)/("cosec" 49°)` 

II. 8.Page 233

Evaluate without using a trigonometric table:

`(sin 32° cos 58° + cos 32° sin 58°)/(tan20°  tan 70°)`

II. 9.Page 233

Evaluate without using a trigonometric table:

cos 44° cosec 46° + tan 30° tan 60° − `sqrt2` cos 45° + tan2 60°

III. 1.Page 233

Simplify:

sin θ sin (90° − θ) − cos θ cos (90° − θ)

III. 2.Page 233

Simplify:

cot (90° − θ) x `sin (90° − θ)/cos (90° − θ)`

EXERCISE 19C [Pages 236 - 237]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई 19 Trigonometry EXERCISE 19C [Pages 236 - 237]

I. 1.Page 236

Find the value of:

(2 cos 0° + sin 45°)(tan 45° − cos 45° + sin 90°)

I. 2.Page 236

Find the value of:

`(4 sin 60° + (cos 60°)/(sin 30°)) (4 cos 30° − 2 sin 30°)` 

I. 3.Page 236

Find the value of:

`4 (sin^2 30° + cos^2 60°) − 3 (cos^2 45° − 1/2  sin^2 90°)`

I. 4.Page 236

Find the value of:

1 – 2 cos2 60° + sin 30°

I. 5.Page 236

Find the value of:

2 tan2 30° − tan2 45° + tan2 60°

I. 6.Page 236

Find the value of:

`(2 cos 30°)/(cos^2 45°) + (tan 60°)/(sin 60° xx tan 30°)`

I. 7.Page 236

Find the value of:

`sqrt((1-sin^2 30°)/(1- cos^2 30°))`

I. 8.Page 236

Find the value of:

tan2 60° cosec2 45° + sec2 60° sin 30°

II. 1.Page 237

Find θ if 0° < θ ≤ 90°.

2 sin2 θ + cos2 45° = tan2 45°

II. 2.Page 237

Find θ if 0° < θ ≤ 90°.

sin θ = `(2 tan 30°)/(1 + tan^2 30°)`

II. 3.Page 237

Find θ if 0° < θ ≤ 90°.

cos θ = 4 cos3 30° − 3 cos 30°

II. 4.Page 237

Find θ if 0° < θ ≤ 90°.

tan θ = sin 30° cos 60° + cos 30° sin 60°

II. 5.Page 237

Find θ if 0° < θ ≤ 90°.

sin θ = 3 sin 30° − 4 sin3 30°

II. 6.Page 237

Find θ if 0° < θ ≤ 90°.

cos θ = cos 60° cos 30° + sin 60° sin 30°

II. 7Page 237

Find θ if 0° < θ ≤ 90°.

`sin^2 θ + cos^2 30° = 5/4`

II. 8Page 237

Find θ if 0° < θ ≤ 90°.

cos θ = 2 cos2 30° − 1

III. 1.Page 237

Find the measure of angle θ in the following when θ is acute.

sin `(θ/3 + 10°) = 1/2`

III. 2.Page 237

Find the measure of angle θ in the following when θ is acute.

2 cos2 5θ = 1

III. 3.Page 237

Find the measure of angle θ in the following when θ is acute.

tan 3θ − 1 = 0

III. 4.Page 237

Find the measure of angle θ in the following when θ is acute.

4 cos2 θ − 3 = 0

show that 4 cos3 θ − 3 cos θ = cos 3θ

III. 5.Page 237

Find the measure of angle θ in the following when θ is acute.

3 tan2 θ = 1

show that `(2 tan θ)/(1− tan^2 θ )= tan 2θ`

III. 6.Page 237

Find the measure of angle θ in the following when θ is acute.

2 sin θ − 1 = 0

show that sin 3θ = 3 sin θ − 4 sin3 θ

IV. 1.Page 237

Find the measure of angles A and B in the following, where A and B are acute.

sin (A+ B) = `sqrt3/2 and cos 2A = 1/2`

IV. 2.Page 237

Find the measure of angles A and B in the following, where A and B are acute.

2 cos 3B = 1 and sin (A + B) = 1

IV. 3.Page 237

Find the measure of angles A and B in the following, where A and B are acute.

cos `((A + B)/2) = 1/ sqrt2 and 2 sin (A − B) = 1`

IV. 4.Page 237

Find the measure of angles A and B in the following, where A and B are acute.

2 sin (2A − B) = 1 and tan `((2A + B)/2) = 1/sqrt3`

MULTIPLE CHOICE QUESTIONS. [Pages 237 - 238]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई 19 Trigonometry MULTIPLE CHOICE QUESTIONS. [Pages 237 - 238]

1.Page 237

sin 30° − tan 45° + cos 60° is ______.

  • 0

  • −1

  • `sqrt3/2`

  • 2

2.Page 237

4 tan 45° – 2 cos 60°

  • 0

  • 4 − `sqrt3`

  • 3

  • 2

3.Page 237

cos2 30° + sin2 30°

  • `sqrt3/2 + 1/4`

  • `5/4`

  • 1

  • `(sqrt3 + 1)/2`

4.Page 237

tan2 30° − tan2 45° + tan2 60°

  • `2 1/3`

  • `8 1/3`

  • `−3 2/3`

  • 0

5.Page 237

sec 60° − sin2 30°

  • `2/sqrt3 − 1/4`

  • `1 3/4` 

  • `1 1/2`

  • `2 1/4`

6.Page 237

cos2 45° − sin2 90°

  • 0

  • `1/2`

  • `− 1/2`

  • 1

7.Page 237

`(sin 60°)/(tan 60°)`

  • `sqrt3/2`

  • `1/2`

  • `1/sqrt3`

  • `sqrt3`

8.Page 237

3 sin2 45° + 2 cos2 60° + cot2 30°

  • 1

  • 2

  • 3

  • 5

9.Page 238

cos2 45° + sin2 60° + sin2 30° = ______.

  • 1

  • `1 1/4`

  • `1 1/2`

  • `1 1/3`

10.Page 238

cos 0° + sec 60° = ______.

  • 2

  • 3

  • 1

  • `1 1/2`

11.Page 238

sec θ + tan θ = ______.

  • 0

  • 1

  • 2

  • 3

12.Page 238

sinθ + cosθ = ______.

  • 1

  • `1 2/5`

  • 2

  • 3

13.Page 238

sin B + tan C = ______.

  • `1/2`

  • `17/15`

  • `4/3`

  • `3/4`

14.Page 238

If 3 sin θ = 4 cos θ, then cot θ = ______.

  • `3/4`

  • `4/3`

  • `1/5`

  • `7/5`

15.Page 238

sin 43° = cos θ, ∴ θ = ______.

  • 43°

  • 47°

  • 57°

  • 133°

16.Page 238

5 tan θ = 4, ∴ sin θ = ______.

  • 4

  • `4/3`

  • `4/sqrt41`

  • `3/4`

17.Page 238

cos 2θ = sin θ, ∴ θ = ______.

  • 90°

  • 60°

  • 30°

18.Page 238

tan 3θ = 1, ∴ θ = ______.

  • 45°

  • 15°

  • 20°

  • 10°

19.Page 238

cos2 θ = `3/4` ∴ θ = ______.

  • 60°

  • 45°

  • 30°

  • 90°

20.Page 238

If θ = 30° then 3 sin θ − 4 sin3 θ = ______.

  • 0

  • −1

  • 1

  • `−1/2`

Direction for Questions 21 to 27: In each of the following questions, a statement of assertion (A) is given and a statement of Reason (R) given below it choose the correct option for each question.

21.Page 238

Assertion (A): In ΔABC, ∠B = 90°, sin C = 0.6, then cos A = 0.8.

Reason (R): sin C = cos (90 − C) = cos A.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A

  • A is true but R is false.

  • A is false but R is true.

22.Page 238

Assertion (A): tan 23° tan 45° tan 67° = 1.

Reason (R): tan 23° tan 67° = tan 23° cot(90° − 67°) = tan 23° cot 23° = 1 and tan 45° = 1.

  • Both A and R are true and R is the correct reason for A.

  • Both A and Rare true but R is the incorrect reason for A

  • A is true but R is false.

  • A is false but R is true.

23.Page 238

Assertion (A): If 2 sin2 θ = 1 then θ = 30°.

Reason (R): sin 30° = `1/2`.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

24.Page 238

Assertion (A): tan2 60° × sec2 45° = 6.

Reason (R): tan 60° = `sqrt3, cos 45° = 1/sqrt2`

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

25.Page 238

Assertion (A): sin2 42° + sin2 48° = 1

Reason (R): sin2 42° + sin2 48° = sin2 (42° + 48°) = sin2 90° = 1

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

26.Page 238

Assertion (A): 5 tan θ = 4 then sin θ = 4, cos θ = 5

Reason (R): tan θ = `sin θ/cos θ`

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

27.Page 238

Assertion (A): If tan A = 1, then 2 sin A cos A= 1

Reason (R): tan 45° = 1

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

MISCELLANEOUS EXERCISE [Page 239]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई 19 Trigonometry MISCELLANEOUS EXERCISE [Page 239]

I. 1.Page 239

Find the value of the following without using a table:

tan 30° × tan 60° + cos 0° + sec 60°

I. 2.Page 239

Find the value of the following without using a table:

sin2 30° + cos2 60° + cosec 30°

II. 1.Page 239

Do as directed:

2 cos2 θ − 1 = 0, find θ, tan θ, sin 2θ and sin2 θ.

II. 2.Page 239

Do as directed:

sin θ = 0.96, find the value of cot θ + cosec θ.

III. 1.Page 239

Find the angle θ, when 0° < θ < 90°.

3 tan2 (θ + 10°) = 1, 0° < θ < 90°

III. 2.Page 239

Find the angle θ when 0° < θ < 90°.

(tan2 θ − 3)(2 sin 3θ − 1) = 0

III. 3.Page 239

Find the angle θ, when 0° < θ < 90°.

cos θ = cos2 30° − sin2 30°

III. 4.Page 239

Find the angle θ when 0° < θ < 90°.

sin 8 = 2 sin 30° cos 30°

IV. 1.Page 239

Evaluate the following without using a table:

`2 (tan 32°)/(cot 58°) + (sec 46°)/("cosec" 44°)`

IV. 2.Page 239

Evaluate the following without using a table:

3 tan 28° tan 62° − `(sec 36°)/("cosec" 54°) + (sin 28°)/(cos 62°)`

IV. 3.Page 239

Evaluate the following without using a table:

sin 34° sec 56° + 4 cos 43° cosec 47°

IV. 4.Page 239

Evaluate the following without using a table:

`(sin 42°)/(sec 48°) + (cos 42°)/("cosec" 48°)`

IV. 5.Page 239

Evaluate the following without using a table:

`(sec 17°)/("cosec" 73°) + (tan 68°)/(cot 22°)` + cos 44° cosec 46°

IV. 6.Page 239

Evaluate the following without using a table:

`(sin 35° cos 55° + cos 35° sin 55°)/("cosec" 10° cos 80°)`

IV. 7.Page 239

Evaluate the following without using a table:

`(tan 36°)/(cot 54°)` + sin 26° sec 64°

IV. 8.Page 239

Without using tables, evaluate the following: 4(sin430° + cos460°) - 3(cos245° - sin290°).

IV. 9.Page 239

Evaluate the following without using a table:

2 tan 18° tan 72° − cot2 30° + cos 34° cosec 56°

IV. 10.Page 239

Evaluate tan 35° tan 40° tan 45° tan 50° tan 55°

V.Page 239

In the figure given alongside, AB = 6 cm, AC = 10 cm, ∠B = 90° and EC = 21 cm.

Find:

  1. AD and AE
  2. cos θ + sin θ
  3. cot α + cosec α.

VI.Page 239

In the given figure, find the value of

  1. sin α + cos α
  2. tan β − cosec β

Solutions for 19: Trigonometry

EXERCISE 19AEXERCISE 19BEXERCISE 19CMULTIPLE CHOICE QUESTIONS.MISCELLANEOUS EXERCISE
B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई chapter 19 - Trigonometry - Shaalaa.com

B Nirmala Shastry solutions for मॅथेमॅटिक्स [अंग्रेजी] कक्षा ९ आयसीएसई chapter 19 - Trigonometry

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