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प्रश्न
If sin θ = `5/13`, find sec θ + tan θ.
योग
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उत्तर
Given:
sin θ = `5/13`
find:
sec θ + tan θ.
Sin θ = `"opposit"/"hypotenuse" = 5/13`
Using Pythagoras:
adjacent = `sqrt(13^2 − 5^2) = sqrt(169 − 25) = sqrt144 = 12`
cos θ = `"adjacent"/"hypotenuse" = 12/13`
sec θ = `1/cos θ = 13/12`
tan θ = `"opposit"/"adjacent" = 5/12`
sec θ + tan θ = `13/12 + 5/12 = 18/12`
sec θ + tan θ = `1 1/2`
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