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Find θ if 0° < θ ≤ 90°. sin2⁡θ +cos2⁡30 ° =54 - Mathematics

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प्रश्न

Find θ if 0° < θ ≤ 90°.

`sin^2 θ + cos^2 30° = 5/4`

योग
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उत्तर

Given:

0° < θ ≤ 90°

`sin^2 θ + cos^2 30° = 5/4` 

cos 30° = `sqrt3/2 → cos^2 30° = 3/4`

`sin^2 θ = 5/4 − 3/4 = 1/2`

`sin θ = 1/sqrt2 = sqrt2/2`   [θ in first quadrant]

θ = 45°

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Trigonometry - EXERCISE 19C [पृष्ठ २३७]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 19 Trigonometry
EXERCISE 19C | Q II. 7 | पृष्ठ २३७
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