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प्रश्न
Find the measure of angle θ in the following when θ is acute.
tan 3θ − 1 = 0
योग
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उत्तर
Given:
tan 3θ − 1 = 0
tan 3θ = 1
tan x = 1 → x = 45° + 180°
Since θ is acute, 0° < θ < 90° ⇒ 0° < 3θ < 270°
In this range the allowable values are
3θ = 45° or 225°
`θ = (45°)/3 = 15° or θ = (225°)/3 = 75°`
θ = 15° or θ = 75°
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