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Find the angle θ in the following, if 0° < θ < 90°. tan θ2 =cot⁡2⁢θ - Mathematics

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प्रश्न

Find the angle θ in the following, if 0° < θ < 90°.

tan `θ/2 = cot 2θ`

योग
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उत्तर

cot x = tan (90° − x)

tan `θ/2` = cot 2θ

Replace cot ⁡2θ with tan ⁡(90° − 2θ):

tan `θ/2` = tan (90° − 2θ)

For 0° < θ < 90° we can equate angles:

`θ/2 = 90° − 2θ`

`θ/2​ + 2θ = 90°`

`(θ + 40)/2 = 90°`

`(θ + 4θ​)/2 = 90°`

`(5θ)/2​ = 90°`

θ = 36°

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Trigonometry - EXERCISE 19B [पृष्ठ २३३]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 19 Trigonometry
EXERCISE 19B | Q I. 5 | पृष्ठ २३३
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