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प्रश्न
Find the angle θ in the following, if 0° < θ < 90°.
tan `θ/2 = cot 2θ`
योग
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उत्तर
cot x = tan (90° − x)
tan `θ/2` = cot 2θ
Replace cot 2θ with tan (90° − 2θ):
tan `θ/2` = tan (90° − 2θ)
For 0° < θ < 90° we can equate angles:
`θ/2 = 90° − 2θ`
`θ/2 + 2θ = 90°`
`(θ + 40)/2 = 90°`
`(θ + 4θ)/2 = 90°`
`(5θ)/2 = 90°`
θ = 36°
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