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प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
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उत्तर
The oxidation of glucose with bromine water (which is a mild oxidizing agent) forms gluconic acid. This indicates presence of aldehyde group.
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संबंधित प्रश्न
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
Glucose on reaction with HI gives n-hexane. What does it suggest about the structure of glucose?
Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(iodoform, acetaldehyde, positive, greater, acidic, acetone, disaccharide, negative, increases, glucose, decreases, chloroform, polysaccharide, lactose, lesser, basic, cationic hydrolysis, anionic hydrolysis)
Sucrose is a _________ and yields upon hydrolysis, a mixture of ________ and fructose.
The following compound can be called as:
The spatial arrangement of the given molecule is denoted by:
Choose the appropriate answer(s) for the below representation from the options given
Oxime is formed by treating glucose with ____________.
Which one of the following compounds is different from the rest?
Glucose reacts with acetic anhydride to form ______.
Which of the following reactions of glucose can be explained only by its cyclic structure?
The α-D glucose and β-D glucose differ from each other due to difference in carbon atom with respect to its ____________.
The number of chiral carbons in ß-D(+) glucose is ____________.
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
Which of the following pairs represents anomers?
Why does compound (A) given below not form an oxime?
(A)
Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?
On the basis of which evidences D-glucose was assigned the following structure?
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]
What happens when D-glucose is treated with the following reagent?
HI
Account for the following:
There are 5 OH groups in glucose
Account for the following:
What happens when D – glucose is treated with the following reagents
Bromine water
Account for the following:
What happens when D – glucose is treated with the following reagents
HNO3
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
The reagents with which glucose does not react to give the corresponding tests/products are:
- Tollen’s reagent
- Schiff’s reagent
- HCN
- NH2OH
- NaHSO3
Choose the correct options from the given below:
