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प्रश्न
Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?
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उत्तर
Following reactions and facts could not be explained by open-chain structures of glucose.
• Despite having the aldehyde group, glucose does not give 2, 4 − DNP test, Schiff's test and it does not form the hydrogen sulphide addition product with \[\ce{NaHSO3}\].
• The pentaacetate of glucose does not react with hydroxylamine indicating the absence of a free −CHO group.
It was proposed that one of the −OH groups may add to the −CHO group and form a cyclic hemiacetal structure. It was found that glucose forms a six-membered ring in which −OH at C − 5 is involved in a ring formation.
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संबंधित प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
What happens when glucose is treated with hydroxylamine?
Enlist the properties of glucose that can not be explained on the basis of open chain structure of it
Write the product when D-glucose reacts with conc. HNO3.
Glucose on reaction with HI gives n-hexane. What does it suggest about the structure of glucose?
Write the reactions involved when D-glucose is treated with the following reagent:
H2N-OH
The following compound can be called as:
Choose the appropriate answer(s) for the below representation from the options given
What is the most abundant organic compound on earth?
Acetylation of glucose yields ____________.
When glucose reacts with bromine water, the main product is ____________.
The reaction of glucose with red P + HI is called ____________.
Which is the least stable form of glucose?
The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:
The letter D and L in carbohydrates represent ____________.
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
When D-glucose reacts with HI, it forms ______.
