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Water is dripping out at a steady rate of 1 cu cm/sec through a tiny hole at the vertex of the conical vessel, whose axis is vertical. When the slant height of water in the vessel is 4 cm, find the

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प्रश्न

Water is dripping out at a steady rate of 1 cu cm/sec through a tiny hole at the vertex of the conical vessel, whose axis is vertical. When the slant height of water in the vessel is 4 cm, find the rate of decrease of slant height, where the vertical angle of the conical vessel is `pi/6`

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उत्तर


Given that `"dv"/"dt"` = 1 cm3/s

Where v is the volume of water in the conical vessel.

From the Fig. 6.2, l = 4 cm

h = `"l" cos  pi/6`

= `sqrt(3)/2 "l"` and r = `"l" sin  pi/6 = "l"/2`.

Therefore, v = `1/3 pi"r"^2"h"`

= `pi/3  "l"^2/4 sqrt(3)/2 "l"`

= `(sqrt(3)pi)/24 "l"^3`

`"dv"/"dt" = (sqrt(3)pi)/8 "l"^2 "dl"/"dt"`

Therefore, l = `(sqrt(3)pi)/8 16 * "dl"/"dt"`

⇒ `"dl"/"dt" = 1/(2sqrt(3)pi)` cm/s.

Therefore, the rate of decrease of slant height = `1/(2sqrt(3)pi)` cm/s

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अध्याय 6: Application Of Derivatives - Solved Examples [पृष्ठ १२४]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 6 Application Of Derivatives
Solved Examples | Q 11 | पृष्ठ १२४

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