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A balloon, which always remains spherical has a variable radius. Find the rate at which its volume is increasing with the radius when the later is 10 cm.

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प्रश्न

A balloon, which always remains spherical has a variable radius. Find the rate at which its volume is increasing with the radius when the later is 10 cm.

योग
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उत्तर

Let the volume of the sun = V and radius = r

`therefore V = 4/3 pir^3`

`therefore (dV)/(dr) = 4/3 pi xx 3  r^2 = 4 pir^2`

`(dV)/(dr) = 4pi xx 10 xx 10`          ...[∴  r = 10 cm]

= 400 `pi` cm3/s

Thus, when the radius is 10 cm, the volume of the balloon increases at a rate of 400 π cm2/s.

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अध्याय 6: Application of Derivatives - Exercise 6.1 [पृष्ठ १९८]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.1 | Q 9 | पृष्ठ १९८

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