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If the circumference of circle is increasing at the constant rate, prove that rate of change of area of circle is directly proportional to its radius.

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प्रश्न

If the circumference of circle is increasing at the constant rate, prove that rate of change of area of circle is directly proportional to its radius.

योग
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उत्तर

Let, the radius of a circle be r .

We have, C = 2πr and let `(dC)/dt` = k  ...(i)

Now, A = πr2

`(dA)/dt = 2πr (dr)/dt`  ...(ii)

and `(dC)/dt = 2π (dr)/dt`

k = `2π (dr)/dt`  ...[From (i)]

`\implies (dr)/dt = k/(2π)`  ...(iii)

Put the value of `(dr)/dt` from equation (iii) in (ii)

`\implies (dA)/dt = 2πr xx k/(2π)` = kr

`implies (dA)/dt ∝ r`

Hence Proved.

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