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A particle moves along the curve 3y = ax3 + 1 such that at a point with x-coordinate 1, y-coordinate is changing twice as fast at x-coordinate. Find the value of a.

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प्रश्न

A particle moves along the curve 3y = ax3 + 1 such that at a point with x-coordinate 1, y-coordinate is changing twice as fast at x-coordinate. Find the value of a.

योग
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उत्तर

Given:

3y = ax3 + 1

Differentiate w.r.t. t

`3dy/dt = axx3x^2 dx/dt`

`=> dy/dt = ax^2 dx/dt`

Use given condition at x = 1

`=> dy/dt = 2dx/dt`

`dy/dt = a(1^2) dx/dt adx/dt`

`adx/dt = 2dx/dt`

`dx/dt cancel= 0`

a = 2

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