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The total cost C(x) in rupees associated with the production of x units of an item is given by C(x) = 0.007x3 – 0.003x2 + 15x + 4000. Find the marginal cost when 17 units are produced - Mathematics

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प्रश्न

The total cost C(x) in rupees associated with the production of x units of an item is given by C(x) = 0.007x3 – 0.003x2 + 15x + 4000. Find the marginal cost when 17 units are produced

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उत्तर

C(x) = 0.007x3 - 0.003x2 + 15x + 4000

=>  marginal cost = `(dC)/dx`

`= d/dx (0.007 x ^3 - 0.003x ^2 + 15x  + 4000)`

= 0.007 × 3x2 - 0.003 × 2x + 15

`∴ (MC)_(x = 17)`

= {0.007 × 3(17)2} - {0.003 × 2(17)} + 15

= 6.069 - 0.102 + 15

= 20.967a

∴ Marginal cost (when x = 17) = 20.967.

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अध्याय 6: Application of Derivatives - Exercise 6.1 [पृष्ठ १९८]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.1 | Q 15 | पृष्ठ १९८

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