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If the area of a circle increases at a uniform rate, then prove that perimeter varies inversely as the radius.

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प्रश्न

If the area of a circle increases at a uniform rate, then prove that perimeter varies inversely as the radius

योग
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उत्तर

Let the radius of circle at any time t is r.

Then area of the circle at any time t is A = πr2.

∴ `"d"/"dt" "A" = "d"/"dt"(pi"r"^2)`

⇒ `"dA"/"dt" = 2pi"r" * "dr"/"dt"`  ......(i)

Since the area of a circle increases at a uniform rate,

We have `"dA"/"dt"` = k, where k is a constant  ......(ii)

From (i) and (ii), we get

`2pi"r" * "dr"/"dt"` = k

⇒ `"dr"/"dt" = "k"/(2pi"r") = "k"/(2pi) * (1/"r")`

⇒ `2pi "dr"/"dt" = "k"/"r"`

⇒ `("d"(2pi"r"))/"dt" = "k"/"r"`

⇒ `"dP"/"dt" = "k"/"r"`, where P = 2πr

⇒ `"dP"/"dt" oo 1/"r"`

Thus perimeter varies inversely as the radius.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १३५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 2 | पृष्ठ १३५

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