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Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: xy = log y + C : y′=y21-xy(xy≠1) - Mathematics

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प्रश्न

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

xy = log y + C :  `y' = (y^2)/(1 - xy) (xy != 1)`

योग
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उत्तर

y = logy + C

xy’ + y = `1/y` · y’

y2 + xyy’ = y

⇒ y2 = y’ - xyy’

y2 = y'(1 - xy)

y’ = `y^2/(1- xy)`

∴ xy = log y +  C is a solution of the given differential equation.

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अध्याय 9: Differential Equations - Exercise 9.2 [पृष्ठ ३८५]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 9 Differential Equations
Exercise 9.2 | Q 7 | पृष्ठ ३८५

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