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Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation: xy = log y + C : y′=y21-xy(xy≠1)

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Question

Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

xy = log y + C :  `y' = (y^2)/(1 - xy) (xy != 1)`

Sum
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Solution

y = logy + C

xy’ + y = `1/y` · y’

y2 + xyy’ = y

⇒ y2 = y’ - xyy’

y2 = y'(1 - xy)

y’ = `y^2/(1- xy)`

∴ xy = log y +  C is a solution of the given differential equation.

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Chapter 9: Differential Equations - Exercise 9.2 [Page 385]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 9 Differential Equations
Exercise 9.2 | Q 7 | Page 385

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