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Find the general solution of dydx(x+2y3) dydx = y - Mathematics

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प्रश्न

Find the general solution of `(x + 2y^3)  "dy"/"dx"` = y

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उत्तर

Given equation is `(x + 2y^3)  "dy"/"dx"` = y

⇒ `"dy"/"dx" = y/(x + 2y^3)`

⇒ `"dx"/"dy" = (x + 2y^3)/y`

⇒ `"dx"/"dy" = x/y + (2y^3)/y`

⇒ `"dx"/"dy" - x/y` = 2y3

Here P = `- 1/y` and Q = 2y2.

∴ Integrating factor I.F. = `"e"^(intPdy)`

= `"e"^(int 1/y dy)`

= `"e"^(-log y)`

= `"e"^(log 1/y)`

= `1/y`.

So the solution of the equation is

x.I.F. = `int "Q"."I"."F".  "d"y + "c"`

`x . 1/y = int 2y^2 . 1/y  "d"y + "c"`

⇒ `x/y = 2 int y  "d"y + "c"`

⇒ `x/y = 2. y^2/2 + "c"`

⇒ `x/y = y^2 + "c"`

So x = y3 + cy = y(y2 + c)

Hence, the required solution is x = y(y2 + c).

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 10 | पृष्ठ १९३

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