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Integrating factor of the differential equation ddcosxdydx+ysinx = 1 is ______. - Mathematics

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प्रश्न

Integrating factor of the differential equation `cosx ("d"y)/("d"x) + ysinx` = 1 is ______.

विकल्प

  • cosx

  • tanx

  • secx

  • sinx

MCQ
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उत्तर

Integrating factor of the differential equation `cosx ("d"y)/("d"x) + ysinx` = 1 is secx.

Explanation:

The given differential equation is

`cos x * ("d"y)/("d"x) + y sinx` = 1

⇒ `("d"y)/("d"x) + sinx/cosx y = 1/cosx`

⇒ `("d"y)/("d"x) + tan x  y = secx`

Here, P = tan x and Q = sec x

∴ Integrating factor = `"e"^(int Pdx)`

= `"e"^(int tan x "d"x)`

= `"e"^(log secx)`

= sec x.

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 40 | पृष्ठ १९६

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