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Solution of the differential equation tany sec2xdx + tanx sec2ydy = 0 is ______. - Mathematics

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प्रश्न

Solution of the differential equation tany sec2xdx + tanx sec2ydy = 0 is ______.

विकल्प

  • tanx + tany = k

  • tanx – tany = k

  • `tanx/tany` = k

  • tanx . tany = k

MCQ
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उत्तर

Solution of the differential equation tany sec2xdx + tanx sec2ydy = 0 is tanx . tany = k.

Explanation:

The given differential equation is tan y sec2x dx + tan x sec2y dy = 0

⇒ tan x sec2y dy = – tan y sec2x dx

⇒ `(sec^2y)/tany * "d"y = (-sec^2x)/tanx * "d"x`

Integrating both sides, we get

⇒ `int (sec^2y)/tany "d"y = int (-sec^2x)/tanx  "d"x`

⇒ `log |tan y| = - log |tan x| + log "c"`

⇒ `log |tan y| + log |tan x| = log "c"`

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 41 | पृष्ठ १९६

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