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Solve the differential equation (1 + y2) tan–1xdx + 2y(1 + x2)dy = 0.

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प्रश्न

Solve the differential equation (1 + y2) tan–1xdx + 2y(1 + x2)dy = 0.

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उत्तर

Given differential equation is (1 + y2) tan–1xdx + 2y(1 + x2)dy = 0

⇒ `2y(1 + x^2)"d"y = -(1 + y^2) . tan^-1x . "d"x`

⇒ `(2y)/(1 + y^2) "d"y = (tan^-1x)/(1 + x^2) . "d"x`

Integrating both sides, we get

`int (2y)/(1 + y^2) "d"y = -int (tan^-1x)/(1 + x^2) . "d"x`

⇒ `log|1 + y^2| = - 1/2(tan^-1x)^2 + "c"`

⇒ `1/2 (tan^-1x)^2 + log|1 + y^2|` = c

Which is the required solution.

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अध्याय 9: Differential Equations - Exercise [पृष्ठ १९४]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 9 Differential Equations
Exercise | Q 23 | पृष्ठ १९४

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