हिंदी

The general solution of the differential equation dydxdydx+yx = 1 is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The general solution of the differential equation `"dy"/"dx" + y/x` = 1 is ______.

रिक्त स्थान भरें
Advertisements

उत्तर

The general solution of the differential equation `"dy"/"dx" + y/x` = 1 is `x^2/2 + "C"`.

Explanation:

xy = `x^2/2 + "c"`

I.F. = `"e"^(int 1/x "d"x)`

= elogx

= x and the solution is y.

x = `int x * 1  "d"x = x^2/2 + "C"`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differential Equations - Solved Examples [पृष्ठ १९०]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 9 Differential Equations
Solved Examples | Q 22. (viii) | पृष्ठ १९०

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

The solution of the differential equation dy/dx = sec x – y tan x is:

(A) y sec x = tan x + c

(B) y sec x + tan x = c

(C) sec x = y tan x + c

(D) sec x + y tan x = c


Solve the differential equation `dy/dx -y =e^x`


Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

y = cos x + C : y′ + sin x = 0


Verify that the given function (explicit or implicit) is a solution of the corresponding differential equation:

xy = log y + C :  `y' = (y^2)/(1 - xy) (xy != 1)`


If y = etan x+ (log x)tan x then find dy/dx


Find `(dy)/(dx)` at x = 1, y = `pi/4` if `sin^2 y + cos xy = K`


Write the order of the differential equation associated with the primitive y = C1 + C2 ex + C3 e−2x + C4, where C1, C2, C3, C4 are arbitrary constants.


The solution of the differential equation \[\frac{dy}{dx} - ky = 0, y\left( 0 \right) = 1\] approaches to zero when x → ∞, if


The number of arbitrary constants in the general solution of differential equation of fourth order is


The general solution of a differential equation of the type \[\frac{dx}{dy} + P_1 x = Q_1\] is


Find the general solution of the differential equation \[x \cos \left( \frac{y}{x} \right)\frac{dy}{dx} = y \cos\left( \frac{y}{x} \right) + x .\]


Find the particular solution of the differential equation `(1+y^2)+(x-e^(tan-1 )y)dy/dx=` given that y = 0 when x = 1.

 

\[\frac{dy}{dx} + 1 = e^{x + y}\]


\[\frac{dy}{dx} - y \cot x = cosec\ x\]


\[\frac{dy}{dx} - y \tan x = e^x\]


`y sec^2 x + (y + 7) tan x(dy)/(dx)=0`


`(2ax+x^2)(dy)/(dx)=a^2+2ax`


\[y - x\frac{dy}{dx} = b\left( 1 + x^2 \frac{dy}{dx} \right)\]


\[\frac{dy}{dx} + 2y = \sin 3x\]


\[\frac{dy}{dx} + 5y = \cos 4x\]


\[x\frac{dy}{dx} + x \cos^2 \left( \frac{y}{x} \right) = y\]


For the following differential equation, find the general solution:- \[\frac{dy}{dx} = \sqrt{4 - y^2}, - 2 < y < 2\]


Solve the following differential equation:-

\[x\frac{dy}{dx} + 2y = x^2 \log x\]


Solve the following differential equation:-

\[x \log x\frac{dy}{dx} + y = \frac{2}{x}\log x\]


Find the differential equation of all non-horizontal lines in a plane.


Solution of the differential equation `"dx"/x + "dy"/y` = 0 is ______.


y = x is a particular solution of the differential equation `("d"^2y)/("d"x^2) - x^2 "dy"/"dx" + xy` = x.


If y(t) is a solution of `(1 + "t")"dy"/"dt" - "t"y` = 1 and y(0) = – 1, then show that y(1) = `-1/2`.


Find the general solution of the differential equation `(1 + y^2) + (x - "e"^(tan - 1y)) "dy"/"dx"` = 0.


If y = e–x (Acosx + Bsinx), then y is a solution of ______.


The number of solutions of `("d"y)/("d"x) = (y + 1)/(x - 1)` when y (1) = 2 is ______. 


The general solution of ex cosy dx – ex siny dy = 0 is ______.


The solution of `x ("d"y)/("d"x) + y` = ex is ______.


Solution of the differential equation `("d"y)/("d"x) + y/x` = sec x is ______.


The general solution of the differential equation (ex + 1) ydy = (y + 1) exdx is ______.


Find a particular solution, satisfying the condition `(dy)/(dx) = y tan x ; y = 1` when `x = 0`


If the solution curve of the differential equation `(dy)/(dx) = (x + y - 2)/(x - y)` passes through the point (2, 1) and (k + 1, 2), k > 0, then ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×